Print Only Text Following a Match

I have the following text in a file called n8n-deployment:

...
          image: busybox:1.36
          image: docker.io/n8nio/n8n:2.13.4
          imagePullPolicy: IfNotPresent
...

And I want to use Regex search and match the version of n8n, in this case 2.13.4 should be output.

Here’s how this can be done using Ripgrep (rg) command.

➜ rg -N -o -P 'image.*n8n:\K.*$' n8n-deployment.yaml
2.13.4

Another way to do this is:

➜ rg -oN 'image.*n8n:(.*)' -r '$1' n8n-deployment.yaml
2.13.4

Or, with grep:

➜ grep -o -P 'image.*n8n:\K.*$' n8n-deployment.yaml
2.13.4

Explanation of flags:

• -N, --no-line-number: Suppress line numbers.
• -o, --only-matching: Prints only the matched part of the line, not the entire line.
• -P, --pcre2: Enables Perl-Compatible Regular Expressions, allowing advanced features like \K.
• -r, --replace: Replaces the match with the specified string, often used with capturing groups.